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expand this log : log x/y^6
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Pascal's Triangle (n = 0) 1 (n = 1) 1 1 (n = 2) 1 2 1 (n = 3) 1 3 3 1 (n = 4) 1 4 6 4 1 (n = 5) 1 5 10 10 5 1 (n = 6) 1 6 15 20 15 6 1 Use n = 6 line: 1(x^6)(y^0) + 6(x^5)(y^1) + 15(x^4)(y^2) + 20(x^3)(y^3) + 15(x^2)(y^4) + 6(x^1)(y^5) + 1(x^0)(y^6) So more simply: (x^6) + 6(x^5)(y) + 15(x^4)(y^2) + 20(x^3)(y^3) + 15(x^2)(y^4) + 6(x)(y^5) + (y^6)
thanks:) i think you might be the only one who knows how to do that!
i guess
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