Use the method of sustiution to solve the system of linear equations. 6a=6-b 6a=3-b
u have value of 6a from 1st equation just substitute in 2nd equation like this 6-b=3-b now can u solve for b?
it would be 3b
are u sure about your question??please verify...
would it be 9b because you multiply
no... are you sure thats the question?
I have to find out if there are any solutions no solutions and if there is what is the ordered pair
then there are no solutions
yup that is the question us the method of substiution to solve the system of linear equations
there are no solutions
your question is not correct for any value of a and b.
Okay thank you, that is what I thought but I got a little confused on it
then as @Mayb40 said there will be no solution because for no value b, 6-b=3-b satisfies...
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