Can someone help explain how to do this equations!!
\[\frac{ x^2+9x+20 }{ x^2-25 }\div \frac{ x+4 }{ x-4 }\]
dividing is the same as multiplying by the "inverse" the inverse of a fraction is the fraction flipped: inverse of a/b is b/a so flip the 2nd equation, and multiply
multiply but it says to divide?
Here is an example \[4\div2 \text{ is the same as } 4\cdot \frac{1}{2}\] flip and multiply
k, i'll give it a try
Also, for these problems FIRST always factor the polynomials (which you can for this problem)
notice that the bottom is a difference of squares: (a^2 - b^2) factors to (a+b)(a-b)
\[\frac{ x-4 }{ x-5 }\] this is what i got. is it right?
got it. thanks.
Yes. But if they want "excluded values", (even if you canceled them away), add x≠ 5, x≠ -5, x≠ -4 (amended)
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