Find the product:

(1/7x^2 - 2/5)(1/2x-1/2)=
(1/7x^2)(1/2x)(1/7x^2)(-1/2)(-2/5)(1/2x)(-2/5)(-1/2) =
(1/14x^3)(-1/14x^2)(-1/5x)(1/5)

Can someone explain if I have done this correctly?

Question

Find the product:

(1/7x^2 - 2/5)(1/2x-1/2)=
(1/7x^2)(1/2x)(1/7x^2)(-1/2)(-2/5)(1/2x)(-2/5)(-1/2) =
(1/14x^3)(-1/14x^2)(-1/5x)(1/5)

Can someone explain if I have done this correctly?

zzr0ck3r · Answer

foil
first
(1/7)x^2 * (1/2)x = (1/14)x^3
outer
(1/7)x^2*(-1/2) = -(1/14)x^2
inner
(-2/5)*(1/2)x = (-1/5)x
last
(-2/5)(-1/2) = 1/5 now add them up
(1/14)x^3-(1/4)x^2-(1/5)x + 1/5

anonymous · Answer

ok ty

anonymous · Answer

would the answr be x^5?

zzr0ck3r · Answer

no the answer is the last line I typed

anonymous · Answer

okay, this is because we cannot go any furtherei that they are not like terms?