Question

I need help! I tried but got it wrong.

Write the equation of a line that passes through the point (3, 1) and is parallel to the line y = x + 2.

Answer 1

Y=5/3+2

Answer 2

the slope of the equation y = x + 2 is 1 because the coefficient of x is 1

therefore the slope of the parallel line is also 1

so now just use the point-slope formula \[y - y_1 = m(x-x_1)\]
in this case x1 is 3 because that's the x coordinate; y1 is 1 because that's the y coordinate; m is 1 because like i said earlier the slope is 1

\[\implies y - 1 = 1(x-3)\]
distribute 1 into x-3
\[\implies y - 1 = x-3\]
add 1 to both sides
\[\implies y - 1 + 1 = x - 3+1\]
combine like terms
\[\implies y = x-2\]
did you get that?

Answer 3

feel free to ask anything about what i did

Answer 4

Its actually y=5/3x+2 not y=x+2. I'm sorry