The local radio station is giving away some tickets to the circus.Adult tickets cost the station $ 8 each while children's tickets cost $6. The station wants to spend no more than $172. Let x = the number of adult tickets and y= the number of children's tickets. show all possible solutions by graphing a linear inequality.

Question

parthkohli · Answer

I have some hints in store.
- The money that they spend will be the $\textbf{sum}$ of the money they spend on children and adults.
- The money that they spend on guys will be $\text{number of guys} \times \text{money for 1 guy}$.
- The inequality sign that you use is less than or equal to/$\le$

anonymous · Answer

thank. how to graphing

parthkohli · Answer

http://wolframalpha.com will help. Note that I am not the best teacher when it comes to graphing... :(

sasogeek · Answer

x=number of adult tickets
adult tickets cost $8

hence total amount in $ of adult tickets =  $8x

y=number of children tickets
children tickets cost $6

hence total amount in $ of children tickets = $6y

the total of these tickets if all are sold should be equal to or less that how much is on budget that the radio station wants to spend, aka $172.

hence,
8x + 6y $\le $ 172

sasogeek · Answer

does the above logic make any sense?

anonymous · Answer

Thank you for answer

sasogeek · Answer

can you graph that?