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Mathematics 11 Online
OpenStudy (anonymous):

Inequality question below.

OpenStudy (anonymous):

\[\left(\begin{matrix}2 \\ 3\end{matrix}\right)x + 9 \ge \left(\begin{matrix}1 \\ 3\end{matrix}\right)x +12\]

OpenStudy (asnaseer):

I haven't seen an inequality question like this one before - looks interesting...

OpenStudy (asnaseer):

ok, so first I would collect like terms.

OpenStudy (asnaseer):

so move the terms involving x to the left-hand-side, and all others to the right-hand-side

OpenStudy (anonymous):

I would put |dw:1345402287279:dw|

OpenStudy (anonymous):

so x=9?

OpenStudy (anonymous):

YEAH IT DOES!

OpenStudy (asnaseer):

hang on - are those supposed to be fractions? i.e. is your question:\[\frac{2}{3}x+9\ge\frac{1}{3}x+12\]

OpenStudy (anonymous):

well x > - 9

OpenStudy (anonymous):

yeah, that's my question.

OpenStudy (asnaseer):

ok - the way you wrote that it looks like an inequality with column vectors

OpenStudy (asnaseer):

which is why I said I haven't seen one like it before :)

OpenStudy (anonymous):

whoops! sorry! haha. But it 9 correct?

OpenStudy (asnaseer):

yes, answer comes out as: \(x\ge9\)

OpenStudy (anonymous):

Thank you for the help!

OpenStudy (asnaseer):

you should probably change your user name to algebraexpert now :)

OpenStudy (anonymous):

haha maybe.....I'm not quite sure I feel confident enough to do that. ;)

OpenStudy (asnaseer):

he he - you will be - very soon in my opinion :)

OpenStudy (anonymous):

thank you! you really helped this year...

OpenStudy (asnaseer):

yw - I'm glad I was able to explain things clearly enough to you. :)

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