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what is another way of writing a=logbase4 ^16
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16^a=4
is that correct
\[a=\log_{4}16 \]\[a^4=16\]\[a=2^4\]
No. Base stays base.
\[4^{a}=16\]
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I see log base 4 of 16 as asking the question... How many powers of 4 are in 16. It would be 4 squared is sixteen, so a is 2.
\[a=\log_{4} 16\]Take anti-log of both sides....
\[a^4=16\]\[2^4=16\]a-2
a=2*
It's a log base 4, you would exponentiate both sides to the base of 4. I'm not familiar with a log base 4 anti-log. They use these numbers because it calculates either way. They want you to know the rule.
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\[\log_{b}x=y <=>b ^{y}=x \]
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