2 sec(4pi/3)
What exactly did they ask you to do here?
to evaluate it
Okay, so just use a calculator
i kinda wanted to solve it without using it though
The easiest way to do that is to simply replace \(\pi = 180\) Then you need to remember that \(\large\sec \theta = \frac{\text{hyp}}{\text{adj}}\)
So drawing a right triangle is necessary.
So \[2\sqrt{3}/ 3\]
What happened to the secant?
well yeah: 2sec 2rad3/3
Where'd you get the extra 2?
it was in the problem to begin with
I don't know. I think you have an extra 2 inside of the secant function.
then how would you solve it -___-
You don't know how to find the value of the secant
What you came up with is not correct
obviously not, i'm asking. But as my overall answer i got -4 Have you finished solving it?
Yes, that is correct. Looks like you corrected your own mistakes
oh wow, yay
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