Question

log 2^(2+1)=4 -log2^(x+7)

Answer 1

is that
\[\log 2^{2x+1} = 4-\log 2^{x+7}\]

Answer 2

??

Answer 3

yes

Answer 4

anytime you have an exponent inside a log, you can bring it out front
\[(2x+1)\log 2 = 4 - (x+7)\log 2\]
distribute and combine like terms
\[(3\log 2)x = 4-8\log 2\]
divide
\[x = \frac{4-8\log 2}{3\log 2}\]