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Mathematics 13 Online
OpenStudy (anonymous):

solve for the indicated variables x/a + y/b + z/c = 1 for a V=2(ab+bc+ca) for a

OpenStudy (dumbcow):

ok for the first equation...combine the 2 fractions y/b+z/c into 1 fraction with common denominator "bc" then subtract that from both sides change the 1 to "bc/bc" ....combine to make right side a single fraction then take reciprocal of both sides then multiply both sides by x

OpenStudy (anonymous):

what do you mean by take the reciprocal? why would we need to do that

OpenStudy (anonymous):

can i just multiply both sides by 1/x?

OpenStudy (dumbcow):

because its x/a = some fraction a is in denominator, so to solve for a, i need to take reciprocal you could also cross-multiply here, but its more work

OpenStudy (anonymous):

ill show you how far i have gotten

OpenStudy (dumbcow):

yes you can multiply by 1/x first, then take reciprocal as final step

OpenStudy (anonymous):

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