factorize: x^3-2x^2-2x+6

Question

anonymous · Answer

@shadowfiend @Outkast3r09

hartnn · Answer

are u sure about your question,because it has one negative irrational root and 2 complex conjugate roots...

anonymous · Answer

yeah i am sure

lgbasallote · Answer

it seems it's an application of the rational roots theorem and factor theorem...

anonymous · Answer

can u tell me the methodology to factorise cubic equations?

lgbasallote · Answer

1. Find one of the factors (maybe use rational roots theorem)

2. Divide the polynomial by that factor (the quotient will be a quadratic equation)

3. Factor out that quadratic equation (maybe using quadratic formula)

that's how i do it...

anonymous · Answer

i do follow that method !!!
but then that doesn't get worked out for this prob

lgbasallote · Answer

maybe it's prime then? could be...

lgbasallote · Answer

yeahhh...wolfram cant factor it either :(

lgbasallote · Answer

..well it can. but it isnt pretty

hartnn · Answer

even wolfram giving -1.5986 and 1.8+/-0.718 i ??

anonymous · Answer

yeah bt then i want that solved step by step...i wanted to knw how did they start

lgbasallote · Answer

one thing's for sure...it wasnt algebra

anonymous · Answer

hmm

anonymous · Answer

wat abt this prob : : x^3-2x^2-2x+6

anonymous · Answer

these are actually a part of a big ques... so it ought to be solved to solve the big prob!

hartnn · Answer

its the same problem...

anonymous · Answer

i only see it like x((x-2)x-2)+6