Write the slope-intercept equation for the line that passes through (-4, -3) and (-6, 7). Please show all of your work.
can u first find the slope using the equation m=(y2-y1)/(x2-x1)
m=7 - -3/-6 - -4?
yes but i would write it as \[m=\frac{7-(-3)}{(-6)-(-4)}\] so what u get m as??
I have no idea.
what is 7-(-3)?
-4
- * - = + so 7-(-3)=7+3=10
You want me to fill in the -*-?
i was telling u that product of 2 negatives is + so here 7-(-3) became 7+3 = 10 did u get this?
Ooooh ok, got it
so now tell me what denominator equals?
denominator equals -2
correct :) so what is m??
m=-2?
m=10/(-2)=-5...see the above formula....ok??
m= -3/-2
oh ok
You are the best
so the standard equation is y=mx+c...where u have m now just need to find c you have 2 points for that,choose any 1 say,(-6,7) now u know x,y and m....put it in the equation y=mx+c.....to get c can u?
ok
so give me value of c when u r done...
hartnn I really appreciate everything you have taught me, I have an emergency here at work and I will have to pick this up when I'm done....I'm so sorry.
as u wish ...
Thanks
Can someone please start where hartnn left off last night, I had to take care of an emergency at work and could not finish.
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