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Mathematics 6 Online
OpenStudy (anonymous):

You draw 1 card at random from a well-shuffled deck of 52 cards, put it back, reshuffle, and draw another card at random. The events "get the ace of spades on the first draw" and "get the queen of hearts on the second draw" are independent events. True or False???

OpenStudy (experimentx):

what do you think?? does the previous one affects the outcome of next event?

OpenStudy (experimentx):

try doing this 10 times ... and also try "not to put it back" ... and repeat the event 10 times ... and think what's the difference ..

OpenStudy (anonymous):

im still not sure...

OpenStudy (experimentx):

what's the difference when you "PUT BACK" the cards and "DON'T PUT" it back ...

OpenStudy (anonymous):

one card difference?

OpenStudy (experimentx):

so which is independent and dependent case?

OpenStudy (anonymous):

im not sure what that means... thats why i couldn't answer it...

OpenStudy (experimentx):

one card difference ... this makes difference right?? "PUT BACK" >> which will affect the outcome of next ?? "DON'T PUT BACK" >> which will affect the outcome of next ??

OpenStudy (hba):

First of tell me how many cards are in your deck ?

OpenStudy (experimentx):

If previous outcome = next out come <----(this is independent event) previous outcome \( \neq \) next out come <--- this is dependent event

OpenStudy (hba):

Then tell me How many of spades,hearts,diamond and clubs

OpenStudy (anonymous):

so its false

OpenStudy (experimentx):

"get the ace of spades on the first draw" = "get the queen of hearts on the second draw" do they have the same change?

OpenStudy (experimentx):

*chance ??

OpenStudy (anonymous):

no

OpenStudy (anonymous):

so it's false right?

OpenStudy (experimentx):

looks like i made difficult ...

OpenStudy (experimentx):

do you know probability?

OpenStudy (anonymous):

sort of im really bad at it

OpenStudy (hba):

lol

OpenStudy (experimentx):

well ... i think you should learn this stuff first. Me gotta go ... @hba mind carrying this on??

OpenStudy (anonymous):

so it's true?

OpenStudy (experimentx):

well ... i guess it can't be helped. yes ... this is independent event!!

OpenStudy (anonymous):

thanks for bearing with me

OpenStudy (hba):

@Mayb40 DO U WANT ME TO TELL YOU HOW TO DO THIS ?

OpenStudy (anonymous):

Independent ivents: events for which the occurence of one has no effect on the probability of occurance, thus they are independent

OpenStudy (anonymous):

okay thanks iventor

OpenStudy (anonymous):

it is true as the probability of first event does not depend on second event and vice versa

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