Question

How to solve:
Differentiate y=[In(square root x)] / x

Answer 1

you know that (ln(u))'=u'/u
then use the quotient formula

Answer 2

I derive the answer as (1-2ln(sq root x) / 2x^2 but the given answer is (1 - ln(sq root x)) / x

Answer 3

y= \[\frac{ \ln \sqrt{x} }{ x}\]
This is the equation.

Answer 4

your derivation seems to be correct then....

Answer 5

cot (11pi/6) .. can you help me with this please? i really don't understand it. thankyou. there's a big test coming up and i really don't know how to solve it. thanks!