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How do I solve this by completing the square: (r^2) - 2r - 1 = 0
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first thing move the -1 to the RHS add on both sides the square of half of 2 what do you get?
(r^2) - 2r = 1
That is all I understand so far
what's half of 2?
1
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(r^2) - 2r + (1^2) = 1 + (1^2)
good r^2-2r+1=2 the left handside is a remarkable identity (r-1)^2=2 can you now solve it?
Do you just square the RHS?
no i just added
No, I mean is that what you do next?
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|dw:1345468086680:dw|
i hope you know that if x^2=a then x=sqrt(a) or x=-sqrt(a)
good,you got it
Thanks!
yw,don't forget to move the -1 to the RHS
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Yep :)
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