Question

An electron is accelerated from a very low velocity )0 speed) by the application of potential difference of V volts. if the de broglie wavelenght should change (ie decrease) by 1 % what % increase in V cause it?

Answer 1

If i remember it correctly, we had a relation like this:
\[\lambda=\frac{12.27 A^0}{\sqrt V}\]where \(\lambda\) is De-broglie wavelength and V is Potential difference.

Answer 2

man...wat is this...!!

Answer 3

\(A^0\) is angstrom equivalent to \(10^{-10}\)

Answer 4

Did u get my question @ujjwal

Answer 5

Dude, I gave you the relation. Apply it! Decrease \(\lambda\) by 1% and see what % increase in V does it bring..

Answer 6

And yeah, that relation is exclusively for electrons..

You can use this relation in all cases..\[\lambda=\frac{h}{\sqrt{2mqV}}\]

Answer 7

it is said that velocity is 0

Answer 8

Read the question 10 times and see what is zero...

Answer 9

Have you seen this relation? \[\lambda=\frac{h}{P}\]

Answer 10

yes

Answer 11

but the queestion tells abt energy

Answer 12

And \[P=\sqrt{2mKE}\]And \[KE=qV\]So, \[P=\sqrt{2mqV}\]So, \[\lambda=\frac{h}{\sqrt{2mqV}}\]

Answer 13

yhxx