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f(t)=3t^2-2 find f(k-2)
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replace \(t\) by \(k-2\) be sure to use parentheses
so if \(f(t)=3t^2-2\) then \(f(k-2)=3(k-2)^2-2\) you can clean that up with some algebra if you like
ok so then it would be 3k^2+12-2
no, you have to square first, multiply second, then combine like terms
no
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\[f(k-2)=3(k-2)^2-2=3(k-2)(k-2)-2\] etc there is algebra to do
3(k−2)^2−2 would be 3(k-2)(k-2) -2
yes
yes exactly
3(k^2-2k-2k+4)-2 =3k^2-12k+10
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You got it :D
are u kidding me, i got a warning for my steps?? this is rediculous
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