You roll 2 dice. What is the probability that the sum of the dice is even and 1 die shows a 3?
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OpenStudy (cwrw238):
probability that one die shows a 3 = (1/6)
now for the sum to be even the other die must show one of which values
OpenStudy (anonymous):
hmm... 1, 3, 5?
OpenStudy (cwrw238):
exactly
so whats probability of 1,3 or 5?
OpenStudy (anonymous):
1/2
OpenStudy (cwrw238):
right
now the two events ( the 3 and 1,3,5) are independent so the 2 probabilities are multiplied
1/2 * 1/6
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OpenStudy (anonymous):
1/12
OpenStudy (anonymous):
is it 1/12 then?
OpenStudy (anonymous):
????
OpenStudy (anonymous):
wow it's wrong... it's 5/36
OpenStudy (cwrw238):
hmm - lets look at it again
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OpenStudy (cwrw238):
i've missed something here - yes the 3 can be on either dice -
well if the 3 is on the other dice instead that doubles the probability - giving 1/6
- thats still wrong
OpenStudy (cwrw238):
- oh 2 '3' isn't two events - just one - so that subtracts 1/36 from 1/6
giving 5/36
-this was more complicated than it appears
sorry guy - but we got there in the end
OpenStudy (cwrw238):
do you follow?
all possibilities are
3 and 1
3 and 5
1 and 3
5 and 3
3 and 3
probabilities for each is 1/36
total probabilities = 5/36
- that way was a lot easier!!!