You roll 2 dice. What is the probability that the sum of the dice is even and 1 die shows a 3?
probability that one die shows a 3 = (1/6) now for the sum to be even the other die must show one of which values
hmm... 1, 3, 5?
exactly so whats probability of 1,3 or 5?
1/2
right now the two events ( the 3 and 1,3,5) are independent so the 2 probabilities are multiplied 1/2 * 1/6
1/12
is it 1/12 then?
????
wow it's wrong... it's 5/36
hmm - lets look at it again
i've missed something here - yes the 3 can be on either dice - well if the 3 is on the other dice instead that doubles the probability - giving 1/6 - thats still wrong
- oh 2 '3' isn't two events - just one - so that subtracts 1/36 from 1/6 giving 5/36 -this was more complicated than it appears sorry guy - but we got there in the end
do you follow? all possibilities are 3 and 1 3 and 5 1 and 3 5 and 3 3 and 3 probabilities for each is 1/36 total probabilities = 5/36 - that way was a lot easier!!!
lol
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