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Can someone help me? I know the answer is A but can someone show me how? Thanks! Solve. 2/ X+3 < 0 A x < –3 B x > 3 C x > –3 D x < 3
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\[\frac 2x+3<0\] or \[\frac 2{x+3}<0\] ???
2/ X+3 < 0
that doesnt clear it up any for me
no the second one!
do u divide 2 by x+3
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lol, thats better :)
haah sorry
since there is not actual "0" value, we have to consider the values that make the bottom go zero
since x+3 = 0 when x=-3 we need to check "sides" now
|dw:1345488066073:dw|
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when x=0, 2/3 < 0 is false which means the other side is true by default|dw:1345488141446:dw|
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