Question

a ball is dropped from a height of 500 feet. after how many seconds will it hit the ground ?

Answer 1

height equation
\[y=at^2+vt+y_0\]
a is acceleration
v is initial velocity
y_0 is initial height

acceleration in imperial units is -32.2 ft/sec^2 (this is a constant that can easily be looked up)
there is no initial velocity because I'm assuming its being dropped from rest
the initial height its being dropped from is 500 ft

so you want the time when it reaches the ground
set y=0
substitute the values and solve for t

Answer 2

do u have an idea on kinetic and potential energy?

Answer 3

they asked us to use the function f(t)=-16t^2+500

Answer 4

sorry i wrote that wrong
it should be \[\frac{1}{2}at^2+v_ot+x\]
if you plug those in, you'd get the same function