Question

1-3over4 (c+2)=-5

Answer 1

need help n explain it to me

Answer 2

\[1-\frac{3}{4}(c+2)=-5\]
is this it?
and assuming you need to solve for c

Answer 3

yes

Answer 4

the goal here is to get c all by itself on one side

however, if you want to add, subtract, multiply,divide anything to one side to get rid of something, the same must be done to the other side

so starting with what's given
we want to get rid of the 1 on the left side, this can be done by subtracting one to both sides
\[1- \frac{3}{4}(c+2)-1=-5-1\]
\[- \frac{3}{4}(c+2)-1=-6\]

Answer 5

can you solve it from here?

Answer 6

umm cant :(

Answer 7

ok well we want to get rid of the -3/4

what can we multiply to that to make it equal to 1?

Answer 8

ok

Answer 9

do u +2 to both sides

Answer 10

is it equal 6
the answer

Answer 11

im going to assume you did all the steps yourself,
yes 6 is the answer

Answer 12

actually because you're solving for c
the answer is
c=6

Answer 13

ok thxs can u jux put that in answer n show all the work please

Answer 14

can u double check this for me

Answer 15

k one sec

Answer 16

yes

Answer 17

k one sec
\[1- \frac{3}{4}(c+2)=-5\]
\[1- \frac{3}{4}(c+2)-1=-5-1\]
\[- \frac{3}{4}(c+2)=-6\]
\[(-\frac{4}{3})(- \frac{3}{4})(c+2)=-6(-\frac{4}{3})\]
kinda combined multiply by -1, multiplying by 4, and dividing by 3 together
\[c+2=8\]
\[c+2-2=8-2\]
\[c=6\]

Answer 18

remember, anything you do to one side, you always need to do it to the other, otherwise it wouldnt be a balanced equation anymore

Answer 19

thxs