f g(x) = 3x + 5, what is g–1(x)?
if not f*
inverse of g?
yeah g^-1
you mean g^-1(x)|dw:1345501377082:dw|
sorry I typed this and then posted it without checking it.
it is ok :)
g-1(x) is the inverse of g(x) g(x) = 3x + 5 find x in terms of g(x) 3x = g(x) - 5 can you now find x ? then replace g(x) by x and x by g(-1)x and thats your inverse
it is 3x + 5=g(x)=y solve for x then switch variables (y and x)
wait what? Im lost
you take 3x+5=y and switch the variables? so its 3y+5=x?
is it x+5/3?
you made a small eror in the sign of the result - please re-check your answer
okay hold on
remember you started with: g(x) = y = 3x + 5 and then swapped x/y variables to get: x = 3y + 5
ok...
so now you need to re-arrange the last expression so that you end up with "y = ..." do you know how to do that?
subtract 3y from both sides
x-3y=5 then you subtract x from both sides. so -3y=-x-5
well first we can just swap the left and right hand sides to get: 3y + 5 = x
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