I have to draw my question...click on this to see the math question, please!!
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one angle is 68 degrees
the hypotenus is 9
you have to solve the right triangle, and round each side the nearest hundreth.
sounds like a job for sines and cosines huh
would i use a^2 + b^2=c^2?
First, J is 180-90-68=22 degrees. Now we're going to use the law of sines, with "J,K,L" as angles and "j,k,l" as their opposite sides: \[\begin{align} &\frac{\sin K}{k}=\frac{\sin J}{j}\\ &=\frac{1}{9}=\frac{.37}{j}\\ j= .04 \end{align}\] See if you can do L the same way.
you use \[\sin \theta = \frac{opposite}{hypotenuse}\] and \[\cos \theta = \frac{adjacent}{hypotenuse}\]
Except that I typed that into my calculator wrong. j is 3.37.
i know the hypotenus is 9. but the opposite is a variable, k. i don't really know what sin and cos means
are u using a graphing calculator?
it's in your calculator... sin and cos
k
hello? um, can you give me a moment while i figure this out?
i think i need a bit more help, please
OK, where are you stuck?
i understand how sink/k = sinJ/j, but how did it equal 1/9?
and then, how did you get .37/j? i'm new to the graphing calculator stuff...
This isn't a graphic calculator thing, this is really a trigonometry issue. Have you learned sin, cos, and tan yet?
not yet, i'm just starting geometry this fall
There's no way I know of to get the other sides without trigonometric functions...anyone else?
could you show me the trigonometry way? i have a graphing calculator
You should really understand what those trig functions mean first. So here we go:
k
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