graph the system of equations and state the solution: -3x+y=-3 y=x-3
there are 2 equations: -3x+y=-3 and y=x-3
did you graph them?
well, i got the first equation to look like: y=3x-3. i haven't graphed them yet. how do i do that?
i also have to state the solution
wo we knwo y=3x-3 has a slope of 3 and a y intercept at y = -3 so start on the point where y = -3 and go up 3 and over 1
ok...
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for x, i got (1,0)
and for the next one we know the slope is 1 and y intercept at -3 so start and -3 and go up 1 and over 1
well and we know the solution is (0,-3) because these are linear and they will only have one solution. and we know they both have the same y intercept so the y intercept is the solution
so, y is (0,-3) and x is (1,-2)
we can check this with algebra y = x-3 y = 3x-3 so 3x-3 = x-3 so 3x = x so 3x-x=0 so x(3-1) = 0 so x(2) = 0 and thus x = 0 when x = 0 both 3x-3 and x-3 are -3 thus a slution at (0,-3)
the solution is the pair (x,y) is the point when the two lines cross, so x = 0, and y = -3 so (0,-3)
so, the solution is just (0,-3), right?
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