Can someone please solve? I really appreciate it! I know the answer, just dont know how to get to there!
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OpenStudy (anonymous):
OpenStudy (lgbasallote):
are those choices below? or are they conditions?
OpenStudy (anonymous):
we identify the lcd first, then, we multiply it to both sides.
OpenStudy (anonymous):
By the way, we can still factor 2x-2. r
OpenStudy (anonymous):
(x-1)(x+2)
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OpenStudy (anonymous):
first take lcm and cross multiply,
[ 2x(x+2)+3(x-1) ](2x-2)=-1(x-1)(x+2)
mutiply ,add the corresponding terms you ll get a cubic equation
first value of x is found by trial and error method
when you get first value of x say x=-4,
divide the cubic equation by x+4=0
youll get a quadratic equation solve it and get the values
OpenStudy (anonymous):
shouldnt we do (x-1)(x+2) times 2x-2
OpenStudy (anonymous):
just wait iam typing method
OpenStudy (anonymous):
2x^2+7x-3=-(x+2)/2
OpenStudy (anonymous):
you get equation till here
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OpenStudy (anonymous):
4x^2+16x-x-4
(4x-1)(x+4)=0 solve
OpenStudy (anonymous):
get answer
OpenStudy (anonymous):
where did u get 7x-3
OpenStudy (anonymous):
by taking lcm 2x^2+4x+3x-3/(x-1)(x+2)
OpenStudy (anonymous):
the adding get 2x^2+7x-3
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