Can someone please solve? I really appreciate it! I know the answer, just dont know how to get to there!
are those choices below? or are they conditions?
we identify the lcd first, then, we multiply it to both sides.
By the way, we can still factor 2x-2. r
(x-1)(x+2)
first take lcm and cross multiply, [ 2x(x+2)+3(x-1) ](2x-2)=-1(x-1)(x+2) mutiply ,add the corresponding terms you ll get a cubic equation first value of x is found by trial and error method when you get first value of x say x=-4, divide the cubic equation by x+4=0 youll get a quadratic equation solve it and get the values
shouldnt we do (x-1)(x+2) times 2x-2
just wait iam typing method
2x^2+7x-3=-(x+2)/2
you get equation till here
4x^2+16x-x-4 (4x-1)(x+4)=0 solve
get answer
where did u get 7x-3
by taking lcm 2x^2+4x+3x-3/(x-1)(x+2)
the adding get 2x^2+7x-3
on lhs
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