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OpenStudy (anonymous):
a ball is dropped from a height of 500 feet. after how many seconds will it hit the ground ?
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OpenStudy (anonymous):
what do u think is the accleration due to gravity
OpenStudy (anonymous):
@hubertH
OpenStudy (anonymous):
USE THIS: s=ut + 1/2 at^2
OpenStudy (lgbasallote):
would be wonderful if that equal sign was an absolute value sign instead
OpenStudy (anonymous):
what if i use V=u+at
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OpenStudy (anonymous):
u dont know the final velocity
OpenStudy (anonymous):
answer is 5.8 seconds
OpenStudy (anonymous):
got it? @hubertH
OpenStudy (anonymous):
Also, need to convert 500ft into meter
OpenStudy (anonymous):
IF u will use a=9.81 m/s
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OpenStudy (anonymous):
then i'll use Kinetic energy =potential energy
OpenStudy (anonymous):
I mean a=9.81m/s^2
OpenStudy (anonymous):
YA that can be done......... to calculate final velocity @hubertH
OpenStudy (anonymous):
But that will take some extra time
OpenStudy (anonymous):
@saura how do we convert feet into meters
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OpenStudy (anonymous):
u can use google
OpenStudy (anonymous):
3.28084 feet = 1m
OpenStudy (anonymous):
does that help?
OpenStudy (anonymous):
@ sauravshakya thanks bro the answer is 5,577
OpenStudy (anonymous):
is that correct? i tried both formulas and i got the same answer
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OpenStudy (anonymous):
Yep.......... u r very correct @hubertH
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