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Mathematics
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Simplify completely
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\[\frac{ x ^{2} - 100 }{ x ^{2}-2x-120 } \div \frac{ 6x+60 }{ x-2 }\]
factorize x^2-2x-120 it can be written as (x-12)(x+10) and X^2 - 100 = x^2 - (10)^2= (x+10) (x-10) now try to solve it
what about the second part the 6x+60/x-2?
after you flip to x-2/6x+60 that would factorize into what?
you can write it as x-2/6(x+10)
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after flipping you can cancel some terms.
would it be \[\frac{ x-2 }{ 6(x+12) }\]
it will be x-2/6(x-12)
ohh okay .. thank you!
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