The area of a rectangle is the product of width and length. If a rectangle has length 12m(sqrt21m) and width (sqrt16m) , which of the following is the area of the rectangle?
Area of rectangle= Width x Length/ Length x Width (it's interchangeable and the answer will still remain the same. e.g. 3 x 4=12 and 4 x 3=12) \[12\sqrt{21} \times \sqrt {16}\] If this is how the numbers look like, then all you have to do from here is solve the equation. Do you need help with that?
yah i need help with that
144
and the square root of 16?
4
Yup! Now, your equation would become \[12\sqrt{21} \times 4\] now, what is 4 x 12?
48
Right! :) Now, you have... \[48\sqrt{21}\] as your answer. (If you want a decimal, then I'd use the 144. However, I do not think you need to give a decimal answer so I'm leaving it in radical form.)
Do you kind of get me? :/
yah so that is the answer there is still work to be done
that should be the answer unless your question asks to give the answer as a decimal.
no decimal Thank You So Much!!! :)
You're welcome! :) All the best!
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