Question

the graph of a quadratic function contains the points (-1,1), (-3,0) and (1,0). its axis of symmetry has the equation x=-1. find the formula for f.

Answer 1

y = a(x+1)^2 + b(x+1) + c

find a, b, c

Answer 2

what do i plug in for x ? is it -1, -3 or 1 ?

Answer 3

when x = -1, y = 1

u ll get three equations like this

Answer 4

how do i solve this problem using y=a(x+h)^2+k ? thats how I am suppose to solve it

Answer 5

yes, h = 1

Answer 6

is h always equal to 1 or is it because the symmetry is 1 so the h is equal to 1 ? i mean why h=1 ?

Answer 7

ohh, coz x = -1, so x - -1 means x + 1

Answer 8

ok thank you