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the graph of a quadratic function contains the points (-1,1), (-3,0) and (1,0). its axis of symmetry has the equation x=-1. find the formula for f.
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y = a(x+1)^2 + b(x+1) + c find a, b, c
what do i plug in for x ? is it -1, -3 or 1 ?
when x = -1, y = 1 u ll get three equations like this
how do i solve this problem using y=a(x+h)^2+k ? thats how I am suppose to solve it
yes, h = 1
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is h always equal to 1 or is it because the symmetry is 1 so the h is equal to 1 ? i mean why h=1 ?
ohh, coz x = -1, so x - -1 means x + 1
ok thank you
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