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Solve the equation 2^(3x) = 8^(4x/1/2) for x
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\[2^{3x}=8^{4x-\frac{ 1 }{ 2 }}\]
hint: use the fact that \(8=2^3\)
I don't really see how that helps...
if you use that hint then you will effectively have something like:\[2^x=2^y\]which means you can state that:\[x=y\]
does that make sense now?
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that helps more than you'll ever know....it's the meaning of life...
:D
3x = 12x - 3/2 9x = 3/2 x = 3/18 x = 1/6
all done
Wait! I wrote the equation wrong! It's 2^(3x) = 8*4^(x/1/2)
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use the same hint
but in addition to that use: \(4=2^2\)
Thanks!
yw and I'm glad you finally worked it out! :)
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