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Multiply: x/6y * 3y^2/11
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\[\frac{ x }{ 6y } \times \frac{ 3y ^{2} }{ 11 } = \frac{ 3xy ^{2} }{ 66y }\]
I don't think that's the answer simplified, that's not one of my choices.
it can also be simplified to
\[\frac{ xy }{ 22 }\]
and another question, would it be the x or y variable with 0 restrictions?
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they both have restrictions cause if they = 0 itel become indeterminate
because my answer choices that match are A. \[\frac{ xy }{ 22 } x \neq0\] B. \[\frac{ xy }{ 22 } y \neq 0\]
look at the original fraction. What values of x or y would cause you to divide by 0? (dividing by 0 is not allowed, because it causes an indeterminate value)
I think y. Is that right ?
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