solve 1/x+2/9=1/3 1/x=1/3-2/9 (this is how far i got) I understand it a lil bit, but i still need help
Do the arithmetic on the right side before you try the algebra.
but don't you have to find a common denominator?
yes, you do. what would that be?
would it be 9, 1/x=1/9-2/9?
I like the 2/9, but the 1/9 is confusing - try that again
3/9
That's so much better, I can't tell you! Now evaluate the right side.
so would it be x = 9?....
Bingo!
Watch out, though. Put 9 back in for x in the original problem, and make sure you get a true statement. You have to be very careful when you see an x in the denominator.
ok i will do that, thank you so much for your help
You're welcome. I always respond to questions where the student has tried to start the problem, and explains where she begins to get confused. As a former math teacher, I don't like to just give the answer. Know what I mean?
i do, could you help me with another one?.....this one really really confuses me
Sure
(y^2-y-12)/(y^2-6y+8) by (y^2+2y-15)/(y^2-7y+10)
it wants me to simplify the expression, and i dont understand at all
Tell you what, that's not going to be quick, I've got to go to dinner. Post it and if you're still having a problem when I check later we'll try it. *:23 EDT
ok thank you
BTW - try to factor each of the quadratics. I hope you've done that with your instructor.
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