Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

solve 1/x+2/9=1/3 1/x=1/3-2/9 (this is how far i got) I understand it a lil bit, but i still need help

OpenStudy (noelgreco):

Do the arithmetic on the right side before you try the algebra.

OpenStudy (anonymous):

but don't you have to find a common denominator?

OpenStudy (noelgreco):

yes, you do. what would that be?

OpenStudy (anonymous):

would it be 9, 1/x=1/9-2/9?

OpenStudy (noelgreco):

I like the 2/9, but the 1/9 is confusing - try that again

OpenStudy (anonymous):

3/9

OpenStudy (noelgreco):

That's so much better, I can't tell you! Now evaluate the right side.

OpenStudy (anonymous):

so would it be x = 9?....

OpenStudy (noelgreco):

Bingo!

OpenStudy (noelgreco):

Watch out, though. Put 9 back in for x in the original problem, and make sure you get a true statement. You have to be very careful when you see an x in the denominator.

OpenStudy (anonymous):

ok i will do that, thank you so much for your help

OpenStudy (noelgreco):

You're welcome. I always respond to questions where the student has tried to start the problem, and explains where she begins to get confused. As a former math teacher, I don't like to just give the answer. Know what I mean?

OpenStudy (anonymous):

i do, could you help me with another one?.....this one really really confuses me

OpenStudy (noelgreco):

Sure

OpenStudy (anonymous):

(y^2-y-12)/(y^2-6y+8) by (y^2+2y-15)/(y^2-7y+10)

OpenStudy (anonymous):

it wants me to simplify the expression, and i dont understand at all

OpenStudy (noelgreco):

Tell you what, that's not going to be quick, I've got to go to dinner. Post it and if you're still having a problem when I check later we'll try it. *:23 EDT

OpenStudy (anonymous):

ok thank you

OpenStudy (noelgreco):

BTW - try to factor each of the quadratics. I hope you've done that with your instructor.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!