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find the missing side of special right triangles. leave answer as radicals in simplest form.
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|dw:1345607904438:dw|
use sine law..
but i need it in radical form?!
\[\sin(60)=\frac{7}{x}\] \[\frac{\sqrt{3}}{2}=\frac{7}{x}\] solve the ratio for \(x\)
oh you need \(x\) and \(y\) ?
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yes please!
i need x and y and in radical form! thanks so much ur so kind;)
sides of a 30 60 90 triangle are always the same ratio
ok this is what you do the ratios for a 30-60-90 right triangle are \(1:\sqrt{3}:2\) for short side: long side: hypotenuse you have long side = 7 so \[\frac{7}{\sqrt{3}}:7:\frac{14}{\sqrt{3}}\]
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