Question

Find the limit please! lim[x:1,(x^4-1)/ (x^3-1)]

Answer 1

factor and cancel

Answer 2

@satellite73 How to factor ? :(

Answer 3

\[x^4-1=(x+1)(x-1)(x^2+1)\]
\[x^3-1=(x-1)(x^2+x+1)\]

Answer 4

Thanks. Isnt that a basic algebra I didn't learn that in school :|

Answer 5

top one is difference of two squares
bottom is difference of two cubes

Answer 6

@eyka94 even if you do not know the algebra, you know that if you replace \(x\) by \(1\) you get zero top and bottom
that means you can factor both as \((x-1)(\text{something})\)
you can find the something by division if you have to

Answer 7

@satellite73 Thank you so much ;)

Answer 8

yw