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Find cos(theta) if tan(theta) = (-2/3) and sin(theta) > 0
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Find \[\cos \theta if \tan \theta = -2/3 and \sin \theta >0\]
Here, you know that the tangent is opp/adjacent. Since the sine is positive, it must be in either the first or second quadrant right?
Yes.
So the opposite leg must be positive, therefore since the tangent is negative the adjacent leg must be the negative one. So what quadrant is that?
Oh so you know o and a, you just need to find the h, and you can solve it :P
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Yep.
Lets see what ya got when ya get it.
Thats 2nd quad
Okay:)
Yep.
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\[\frac{ -3 }{ \sqrt{13}}\]
Thats it.
:D thank you!
No prob.
\[\frac{ x \sqrt{\left| x ^{2}-4 \right|} }{ x ^{2}-4 }-1>0\]
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@Yasir_se wtf?
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