Question

Let P(x) + ax^7 + bx^3 +cx -5 where a,b,c are constants. Given that P(-7) = 7, find the value of P(7).

Answer 1

What course are you taking, this is very perplexing to me at least. Hopefully robtobey can solve, it is above my paygrade.

Answer 2

\[ P(x) =ax^7 + bx^3 +cx -5\]?

Answer 3

note that all the exponents are odd numbers

Answer 4

\[-P(7)=-a7^7-b7^3-7c+5=a(-7)^7+b(-7)^3+c(-7)-5+10=P(-7)+10\]does that help?

Answer 5

this is Algebra Grade 9

Answer 6

This helps mulishly

Answer 7

very well :)

Answer 8

what that word means? mulishly?

Answer 9

sorry..I typed your name and the computer recognized it differently . when I clicked "return" it sent that name...mukushla

Answer 10

oh...np..:)