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How do you factor this trinomial: 5x^2-23x+12 step by step?
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Find two numbers that multiply to 5*12 = 60 and add to -23
okay thank you
tell me what you get
(x-3)(x-20)?
-3 and -20 are the two numbers, but that's not the correct factorization
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that trick only works when the leading coefficient is 1
Then what do I do?
Replace -23x with -3x-20x to get 5x^2-23x+12 5x^2-3x-20x+12 Now factor by grouping
By grouping?
Are you familiar with that technique?
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No, not really.
Alright, here's how you factor this by grouping 5x^2-23x+12 5x^2-3x-20x+12 (5x^2-3x)+(-20x+12) x(5x-3)+(-20x+12) x(5x-3)-4(5x-3) (x-4)(5x-3)
Thank you!
np
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