Mathematics
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OpenStudy (anonymous):
What is the product of 5the square root of 3. • 4the square root of 15.? Simplify if possible.
13 years ago
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OpenStudy (anonymous):
\[5\sqrt{3}\times4\sqrt{15}\]
13 years ago
OpenStudy (anonymous):
I think that's as simple as you can go
13 years ago
OpenStudy (anonymous):
\[\large\sqrt[5]{3}\times \sqrt[4]{15}?\]
13 years ago
OpenStudy (anonymous):
either way, that's is as simplified as it will get :)
13 years ago
OpenStudy (anonymous):
that*
13 years ago
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OpenStudy (anonymous):
Ball is on your court. Now let's dance.!
13 years ago
OpenStudy (anonymous):
no its not simplified
13 years ago
OpenStudy (anonymous):
mofo it is simplified
13 years ago
OpenStudy (anonymous):
Well what is the product then?
13 years ago
OpenStudy (anonymous):
(5*4)(rad(3*15))
13 years ago
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OpenStudy (anonymous):
I am to help. I said it is simplifies
13 years ago
OpenStudy (anonymous):
you can do more
13 years ago
OpenStudy (anonymous):
The only thing you can do is multiply the 4 and 5 to get 20
13 years ago
OpenStudy (anonymous):
\[(5\times4)\sqrt{3\times15}\]
13 years ago
OpenStudy (anonymous):
so would it be 20 sqrtrt 15?
13 years ago
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OpenStudy (anonymous):
and you can extract a square root of 3 but that's it
13 years ago
OpenStudy (anonymous):
\(\sqrt{3\times 15}=\sqrt{3^2\times 5}=\sqrt{3^2}\times \sqrt{5}=3\sqrt{5}\)
13 years ago
OpenStudy (anonymous):
\[60 \sqrt{5}\]
13 years ago
OpenStudy (anonymous):
following nick you would get\[20\sqrt{45}\]which can be simplified to \[20\times3\sqrt{5}\]\[60\sqrt{5}\]
13 years ago
OpenStudy (anonymous):
Final answer boyah!
13 years ago
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OpenStudy (anonymous):
Brohoof ?
13 years ago
OpenStudy (anonymous):
Could I also have help on finding the product of 6
square root of the quantity 12 times k. • 4kthe square root of 3.? Simplify if possible.
13 years ago
OpenStudy (anonymous):
do it the same way pound
13 years ago
OpenStudy (anonymous):
Im confused now though, would it be 144k sqrrt 2k?
13 years ago
OpenStudy (anonymous):
\[6\sqrt{12k}\times4k \sqrt{3}\rightarrow(6\times4k)\sqrt{12k \times3}\]
13 years ago
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OpenStudy (anonymous):
(24k) sqrrt36k?
13 years ago
OpenStudy (anonymous):
ya now reduce
13 years ago
OpenStudy (anonymous):
Im confused as to how to reduce this
13 years ago
OpenStudy (anonymous):
72kthe square root of k.
144kthe square root of the quantity 2 times k.
72kthe square root of the quantity 2 times k.
144kthe square root of k.
Those are my possible answers
13 years ago
OpenStudy (anonymous):
?
11 years ago