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Inequalities... 5-3|4x+3|>2
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2|4x+3|>2
|4x+3|=-(4x+3) =-4x-3 & |4x+3|=4x+3
I subtract 3 from all sides now?
one time 2(4x+3)>2 8x+6>2 8x>2-6 8x>-4 x>-4/8 x>-1/2
no... those were not parantheses...
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They were absolute value signs
& one time 2(-4x-3)>2 -8x-6>2 -8x>2+6 -8x>8 x>8/-8 x>-1
Why do you distribute? Those were absolute value signs... not parentheses.
i have convert them into parenthesis
|a|=-a & a
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I know that
so |4x+3|=4x+3 & -(4x+3)
gt it @MathLegend ?
Okay
Now, I can do this for all Inequalites? (Turning the absolute value signs into parentheses?)
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yes!
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