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Using exact values, show that sin^2x-cos^2x= 1
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x=30 degrees
but sin^2x-cos^2x is not equal to 1 sin^2x+cos^2x= 1
nono you gotta use that for each angle. and the angle is x=30 degrees
answer is (1/2)^2 + ( square root 3 / 3 ) ^2 = 1. idk how they got that
*sqaure root 3 / 2
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u see the + sign in between?? thats because of sin^2x+cos^2x and not sin^2x-cos^2x
rest values are correct,sin 30 =1/2 and cos 30 = (sqrt 3)/2
which gives 1/4 + 3/4 =1
ok
damn hartnn went hard on ya lol
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