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add and write in simplest form. 4y over y+2 + 8 over y+2
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when the denoms are the same all u have to do is operate with the numerator which means add them
y^2 - 4y + 4 - 10 = 4 (y - 2)^2 = 14 y - 2 = +/- sqrt(14) y = 2 +/- sqrt(14)
so add 4y and 8?
\[\frac{ 4y+8 }{ y+2}?\]
yes. that looks correct.
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Okay thanks :)
you can simplify it further though.
factorize 4y+8 (Find its GCF)
\[\frac{ 2y+4 }{ y }?\]
no.
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I am confused
\[4(y+2) \over y+2\]
ohhh so then you cancel y+2 and you end up with 4?
yes. I believe so.
Okay. thank you.
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you're welcome.
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