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Mathematics 22 Online
OpenStudy (anonymous):

Two cards are drawn in a row without replacement. What is the probability of drawing three pink cards? (there are 10 pink cards & 4 of them are pink) a.1/30 b.2/15 c.6/45 d.2/9

OpenStudy (anonymous):

i was confused as to what they meant by two cards are drawn in a row, like is it 2 cards, then draw again, or is it draw one card, then another

OpenStudy (phi):

they mean take a card out and do not replace it. you say (there are 10 pink cards & 4 of them are pink) I assume you mean 10 cards, 4 being pink.

OpenStudy (phi):

you start with 10 cards. after 1 pick, you have 9 cards. If the first was pink, you have 3 pink cards

OpenStudy (anonymous):

but if they're only drawing 2 cards, then how are they gonna have any probablility of gettign 3 pink cards

OpenStudy (phi):

they must mean pick 3?

OpenStudy (anonymous):

see thats the part that confused me,

OpenStudy (phi):

maybe they mean draw 2 then draw another 2 (a total of 4 cards) in which case I'll have to think about it.

OpenStudy (phi):

If I did it correctly, I get 5/42 which does not match any of your choices. If you ever get the correct answer, post it

OpenStudy (anonymous):

it's actually 1/30, my teacher didnt understand either, so she just gave me the answer :b

OpenStudy (phi):

1/30 is what you get if you draw 3 cards, one at a time with no replacement: (4/10)*(3/9)*(2/8)

OpenStudy (anonymous):

oh, well idk, but the lesson is online so the teacher gets all the answers

OpenStudy (phi):

FYI, chance of getting 1 pink with (4 pinks, 10 total) is 4/10 you now have 3 pinks out of 9 total in the deck. the chance of getting the 2nd pink is (3 out 9) or 3/9 the chance of getting the 3rd pink is (2 out of 8) or 2/8 you multiply the probabilities to get the probability of getting 3 pinks in a row.

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