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(3x over x-5) - (5 over 5-x)
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\[{3x \over x-5} - {5 \over 5-x} \]
yea
\[\frac{ 3x }{ x-5 }- \frac{ 5 }{ 5-x }= \frac{ 3x }{ x-5 }+ \frac{ 5 }{ x-5 }\]
its the same thing?
\[\frac{ 3x+5 }{ x-5 }\]
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okay so you change it so 3x+5 to change the 5-x to x-5 right?
He distributed the negative into the second equation to make the negatives positive which resulted in the same denominator: x-5. (I believe that is what you're asking?)
yes.
Ok.
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