Question

Add and simplify if possible: x+3/x-4 + x/4-x

Answer 1

Hint:

4-x = -1(x-4)

So

\[\Large \frac{x+3}{x-4}+\frac{x}{4-x}\]


\[\Large \frac{x+3}{x-4}+\frac{x}{-1(x-4)}\]


\[\Large \frac{x+3}{x-4}-\frac{x}{x-4}\]

Answer 2

\[\frac{2x + 3}{ x-4 }\]

Answer 3

is that right?

Answer 4

No,

\[\Large \frac{x+3}{x-4}+\frac{x}{4-x}\]


\[\Large \frac{x+3}{x-4}+\frac{x}{-1(x-4)}\]


\[\Large \frac{x+3}{x-4}-\frac{x}{x-4}\]


\[\Large \frac{x+3-x}{x-4}\]

Answer 5

oh so 3/ x-4

Answer 6

yes, the final answer is

\[\Large \frac{3}{x-4}\]

Answer 7

yea! thanks :)

Answer 8

np