Two similar solids are shown below.
What is the volume of the larger solid?
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OpenStudy (anonymous):
OpenStudy (anonymous):
2624 ft3
1312 ft3
5248 ft3
4386 ft3
OpenStudy (anonymous):
@lgbasallote
OpenStudy (lgbasallote):
first, do you know what is the ratio of the SIDE of the smaller solid to the larger solid?
OpenStudy (anonymous):
is it 2:4
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OpenStudy (lgbasallote):
right
OpenStudy (lgbasallote):
the ratio of their volumes will be the cube of that... so what is
2^3 : 4^3 simplified?
OpenStudy (lgbasallote):
\[\huge \Uparrow 2^3 : 4^3\]
OpenStudy (anonymous):
1/8
OpenStudy (lgbasallote):
no...do it individually..what is 2^3
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OpenStudy (anonymous):
8
OpenStudy (lgbasallote):
and what is 4^3
OpenStudy (anonymous):
64
OpenStudy (lgbasallote):
good so the ratio of the volumes will be 8 : 64
now use proportionality
the volume of the smaller cube is 328 so...
\[\huge \frac {8}{64} = \frac{328}{x}\]
solve for x
OpenStudy (anonymous):
2624
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OpenStudy (anonymous):
how did you get 328
OpenStudy (lgbasallote):
it's given
OpenStudy (anonymous):
nevermind
OpenStudy (lgbasallote):
look at the attachment
OpenStudy (lgbasallote):
lol
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OpenStudy (anonymous):
i know
OpenStudy (anonymous):
do u think u can help me with just one more
OpenStudy (lgbasallote):
sure
OpenStudy (anonymous):
great!!
OpenStudy (lgbasallote):
just tag me when you're ready
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OpenStudy (anonymous):
everything is in the attachment
OpenStudy (anonymous):
@lgbasallote
OpenStudy (lgbasallote):
\[\huge LSA = \frac{ps}{2}\]
where p = perimeter of the base
s = slant height
does that help?
OpenStudy (anonymous):
kind of
OpenStudy (lgbasallote):
good. try and answer it. then when you have an answer let me check
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OpenStudy (anonymous):
so i find the lateral area
OpenStudy (lgbasallote):
yes
OpenStudy (lgbasallote):
remember that the base is an equilateral triangle so the perimeter is just 3b
b = base edge
OpenStudy (anonymous):
is the answer 72??
OpenStudy (lgbasallote):
how did you get 72?
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OpenStudy (anonymous):
I am not really sure this question confuses me
OpenStudy (lgbasallote):
okay first...what is the perimeter of the base?
OpenStudy (anonymous):
16
OpenStudy (lgbasallote):
remember...the base is an equilateral triangle...so the perimeter is 3 x length of base
OpenStudy (lgbasallote):
the base edge is 4... so what is 3 x 4?
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OpenStudy (anonymous):
12
OpenStudy (lgbasallote):
right and the slant height is 11 so \[\huge LSA = \frac{(12)(11)}{2}\]
solve that now