Question

Solve for a.
y=ax^2+bx+c
Please help!

Answer 1

Subtract c from both sides

Then subtract bx from both sides

Answer 2

What's next?

Answer 3

a celebratory party?

Answer 4

...well before that lol

Answer 5

divide x^2?

Answer 6

yes, divide both sides by x^2

Answer 7

I'm a little confused about how to put it all together

Answer 8

\[\Large y=ax^2+bx+c\]


\[\Large y-c=ax^2+bx\]


\[\Large y-c-bx=ax^2\]


\[\Large \frac{y-c-bx}{x^2}=a\]


\[\Large a=\frac{y-c-bx}{x^2}\]

Answer 9

a=c-y/x^2-bx?

Answer 10

close, but see above

Answer 11

is that the same as a=-b/x+y/x^2-c/x^2

Answer 12

yes that's another way to state the answer

Answer 13

Thank you so much!!!

Answer 14

np