Question

Solve the following system using the substitution method.

x + 3y = –5
5x + 6y = –19

a. negative three, negative two–thirds

b. negative three, two–thirds

c. three, negative two–thirds

d. three, two–thirds

Answer 1

a

Answer 2

are you sure?

Answer 3

Start with

x + 3y = –5

and isolate x to get

x + 3y = –5

x = –5-3y

Answer 4

Then move onto

5x + 6y = –19

and replace 'x' with -5-3y since x = -5-3y to get

5x + 6y = –19

5(-5-3y) + 6y = –19

Answer 5

Solve that for y. Then use that solution of y to find the solution for x.

Answer 6

-25 - 15y + 6y = -19
-25 - 9y = -19
+25 + 25
-9 = 6

Answer 7

@jim_thompson5910
6 2
-- = ---
-9 -3

Answer 8

yes, y = -2/3

Answer 9

now find x

Answer 10

im not good with fractions inside of equations

Answer 11

x + 3y = –5


x + 3(-2/3) = –5


x + (3/1)(-2/3) = –5


x + (3(-2))/(1*3) = –5


x + (-6/3) = -5


x - 2 = -5


I'll let you finish

Answer 12

x - 2 = -5
+ 2 + 2
x = -3

Answer 13

you got it

Answer 14

THANK YOU!

Answer 15

np