Question

Find the equations for the lines through the point (a, c) that are parallel to and perpendicular to the line y = mx + b. Assume m ≠ 0.

Parallel y=

perpendicular y=

Answer 1

y-c=m(x-a)
y=mx-am+c eq===> paralel

Answer 2

perpendicular
y-c=-1/m(x-a)
my-mc=-x+a
my=-x+mc+a
y=1/m(-x+mc+a)

Answer 3

can you please explain how to do the perpendicular one?

Answer 4

for perpendicular one the slope will be -1/m

Answer 5

rest will be same

Answer 6

why is it -1/m ???

Answer 7

because the product of slope of perpendicular lines is equal to negative one