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n2 + (n + 1)2 = 85
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n2 + n2 + 2n + 1 = 85
2n2 + 2n - 84 = 0.
Now What Do I Do?
you can divide by 2 to make it easier
\[n^2+n-42=0\] i think this one factors
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Ok I Got That But After That I Dont Know What To do.
did you factor as \((n+7)(n-6)=0\) ?
where does the 7 and 6 come from?
because \(-6\times 7=-42\) and also \(7-6=1\) so when you multiply out, you get \(n^2+n-42\) whic is what you want
so i have to find the LCM Of -42
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